What is the first step in resolving a given rational function into partial fractions?
Answer: a) Factor the denominator
For a rational function with a denominator of the form (x² + 1)(x + 1), the partial fraction decomposition would require how many terms?
Answer: b) 2
What type of partial fraction decomposition is used when the denominator has repeated linear factors?
Answer: c) Generalized partial fractions
Which of the following is the correct partial fraction decomposition for the rational function 3x + 5/(x + 1)(x - 2)?
Answer: a) A/x + 1 + B/x - 2
When resolving partial fractions, the form of the partial fractions will depend on the type of which factor?
Answer: b) Denominator
In the partial fraction decomposition of 1/(x - 2)(x + 3), what are the values of A and B if we equate the rational function to A/x - 2 + B/x + 3?
Answer: c) A = 3, B = -2
What does the term "proper fraction" mean in the context of partial fractions?
Answer: a) The numerator's degree is less than the denominator's degree
Which of the following is the correct decomposition for 4/x(x + 2)?
Answer: a) A/x + B/x + 2
What is the partial fraction decomposition for 2x + 3/(x + 1)(x + 2)?
Answer: b) /x + 2 + /x + 1
Which of the following is true about the partial fraction decomposition of a rational function with repeated factors in the denominator?
Answer: c) Powers of each factor contribute fractions with higher degrees
When a rational function has a denominator of the form (x - 1)2(x + 3), how do we resolve it into partial fractions?
Answer: a) The fraction will have terms of the form /x - 1 + /(x - 1)2 + /x + 3
For a rational function of the form x^2 + 3x + 2/x^3 + x^2 - 2x, what is the first step in the partial fraction decomposition process?
Answer: b) Factor the denominator
Which of the following is the partial fraction decomposition for 1/(x - 3)(x + 4)?
Answer: a) /x - 3 + /x + 4
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