AP ECET PHYSICS Multiple Choice Questions (MCQs)
AP ECET Physics Unit-3: Kinematics and Friction - Multiple Choice Questions
31. What is the equation of motion for an object under uniform acceleration?
- a) \( v = u + at \)
- b) \( v = u + \frac{1}{2}at^2 \)
- c) \( s = ut + \frac{1}{2}at^2 \)
- d) All of the above
Answer: d) All of the above
32. The acceleration due to gravity on the surface of the Earth is approximately:
- a) 9.8 m/s²
- b) 10 m/s²
- c) 11 m/s²
- d) 9.2 m/s²
Answer: a) 9.8 m/s²
33. What is the time of ascent for a body thrown vertically upwards with an initial velocity \( u \)?
- a) \( \frac{u}{g} \)
- b) \( \frac{u}{2g} \)
- c) \( \frac{u^2}{2g} \)
- d) \( \frac{2u}{g} \)
Answer: a) \( \frac{u}{g} \)
34. The time of descent for a body dropped from a height is:
- a) Equal to the time of ascent
- b) Half of the time of ascent
- c) Twice the time of ascent
- d) None of the above
Answer: a) Equal to the time of ascent
35. What is the formula for the maximum height \( H \) reached by a body projected vertically upwards with an initial velocity \( u \)?
- a) \( H = \frac{u^2}{g} \)
- b) \( H = \frac{2u}{g} \)
- c) \( H = \frac{u^2}{2g} \)
- d) \( H = \frac{g}{u} \)
Answer: c) \( H = \frac{u^2}{2g} \)
36. What is the equation for the time of flight for a projectile?
- a) \( T = \frac{2u \sin \theta}{g} \)
- b) \( T = \frac{u \sin \theta}{g} \)
- c) \( T = \frac{u}{g} \)
- d) \( T = \frac{u \cos \theta}{g} \)
Answer: a) \( T = \frac{2u \sin \theta}{g} \)
37. The horizontal range \( R \) of a projectile is given by:
- a) \( R = \frac{u^2 \sin 2\theta}{g} \)
- b) \( R = \frac{u \cos \theta}{g} \)
- c) \( R = \frac{u^2}{g} \)
- d) \( R = \frac{2u}{g} \)
Answer: a) \( R = \frac{u^2 \sin 2\theta}{g} \)
38. The velocity at the point of projection for a body projected obliquely is:
- a) Equal to the horizontal velocity
- b) Equal to the vertical velocity
- c) The vector sum of horizontal and vertical velocities
- d) None of the above
Answer: c) The vector sum of horizontal and vertical velocities
39. The magnitude of the resultant velocity of a projectile at the point of projection is:
- a) \( u \)
- b) \( u \cos \theta \)
- c) \( u \sin \theta \)
- d) \( \sqrt{u^2 + v^2} \)
Answer: a) \( u \)
40. Which of the following is true for the horizontal component of velocity in projectile motion?
- a) It remains constant throughout the flight
- b) It increases with time
- c) It decreases with time
- d) It is zero at the maximum height
Answer: a) It remains constant throughout the flight
41. The velocity at the maximum height of a projectile is:
- a) Zero
- b) Equal to the initial velocity
- c) Equal to the horizontal component of velocity
- d) Equal to the vertical component of velocity
Answer: c) Equal to the horizontal component of velocity
42. What is the acceleration of a projectile at the maximum height?
- a) Zero
- b) \( g \) downward
- c) \( g \) upward
- d) None of the above
Answer: b) \( g \) downward
43. The range of a projectile is maximum when the angle of projection is:
- a) 0°
- b) 45°
- c) 60°
- d) 90°
Answer: b) 45°
44. The path followed by a projectile is:
- a) A circle
- b) A straight line
- c) A parabola
- d) An ellipse
Answer: c) A parabola
45. If a body is projected horizontally from the top of a tower, the time of descent is determined by:
- a) The height of the tower
- b) The initial velocity of projection
- c) The horizontal range
- d) Both a and b
Answer: a) The height of the tower
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