Home Latest Jobs Syllabus Projects Previous Question Papers Entrance Exam Notifications Multiple Choice Question

AP ECET CHEMISTRY Multiple Choice Questions (MCQs)

AP ECET Chemistry - Solutions Questions

AP ECET Chemistry - Solutions Questions (31 to 45)

31. What is the term used for the substance that dissolves in a solution?

a) Solvent

b) Solute

c) Solution

d) Concentration

Answer: b) Solute

32. Which of the following represents the concentration of a solution in terms of moles of solute per liter of solution?

a) Normality

b) Molarity

c) Molality

d) Mass percentage

Answer: b) Molarity

33. What is the normality of a solution that contains 1 mole of HCl dissolved in 1 liter of water?

a) 1 N

b) 2 N

c) 0.5 N

d) 1 M

Answer: a) 1 N

34. What is the term used to define the amount of solute present in a given quantity of solvent or solution?

a) Concentration

b) Volume

c) Density

d) Weight

Answer: a) Concentration

35. Which of the following is used to calculate the molarity of a solution?

a) Molar mass

b) Number of moles of solute / Volume of solution in liters

c) Equivalent weight

d) Mass of solute / Volume of solvent

Answer: b) Number of moles of solute / Volume of solution in liters

36. What is the unit of molarity (M)?

a) Mole/Liter

b) Grams

c) Mole/Volume

d) Grams/Liter

Answer: a) Mole/Liter

37. Which of the following is true about normality?

a) Normality is the number of moles of solute in a given volume of solution

b) Normality is expressed in terms of equivalents of solute per liter of solution

c) Normality has no relation to volume of solution

d) Normality is not used for acid-base titrations

Answer: b) Normality is expressed in terms of equivalents of solute per liter of solution

38. What is the molarity of a solution prepared by dissolving 5 grams of NaOH (Molar mass = 40 g/mol) in 250 mL of solution?

a) 0.5 M

b) 1 M

c) 2 M

d) 0.25 M

Answer: a) 0.5 M

39. What is the formula to calculate equivalent weight of a substance?

a) Equivalent weight = Molar mass / Number of equivalents

b) Equivalent weight = Molar mass / Number of moles

c) Equivalent weight = Mass of solute / Volume of solution

d) Equivalent weight = Volume of solution / Molarity

Answer: a) Equivalent weight = Molar mass / Number of equivalents

40. Which of the following is the correct formula to find normality?

a) N = M × Equivalent weight

b) N = M × Volume

c) N = Number of equivalents / Volume of solution in liters

d) N = Mole / Volume

Answer: c) N = Number of equivalents / Volume of solution in liters

41. A solution is prepared by dissolving 10 grams of KOH (molar mass = 56 g/mol) in 500 mL of water. What is the molarity of the solution?

a) 0.35 M

b) 0.25 M

c) 0.1 M

d) 0.5 M

Answer: b) 0.25 M

42. In a solution, which component is typically present in the larger amount?

a) Solute

b) Solvent

c) Concentration

d) Solution

Answer: b) Solvent

43. What does the term "molarity" refer to in a solution?

a) The number of equivalents of solute in a solution

b) The mass of solute in a given volume of solution

c) The moles of solute per liter of solution

d) The volume of solute in a given mass of solvent

Answer: c) The moles of solute per liter of solution

44. What is the normality of 0.1 M H2SO4 solution? (Note: H2SO4 has 2 replaceable H+ ions per molecule)

a) 0.2 N

b) 0.1 N

c) 2 N

d) 1 N

Answer: a) 0.2 N

45. Which of the following is the correct relationship between molarity (M) and normality (N) for H2SO4?

a) N = M / 2

b) N = 2M

c) N = M

d) N = M × 2

Answer: b) N = 2M

<< Previous Page l Next Page >>

Note/Caution: studentsbizz.com does not promise a job or an interview in exchange for money. Fraudsters may ask you to pay under the pretext of a registration fee or refundable fee, but please be aware that legitimate employers will not require such payments.