JEE (Main) Mathematics - Differential Equations MCQs
JEE (Main) Mathematics - Differential Equations MCQs
Solution of Differential Equations by Separation of Variables
16. The differential equation:
\(\frac{dy}{dx} = y \cdot \sin(x)\)
- \(y = C \cdot e^{\sin(x)}\)
- \(y = C \cdot e^{-\cos(x)}\)
- \(y = C \cdot e^{\cos(x)}\)
- \(y = C \cdot \sin(x)\)
Answer: B
17. Solve the differential equation:
\(\frac{dy}{dx} = x \cdot y\)
- \(y = Ce^x\)
- \(y = Ce^{x^2/2}\)
- \(y = C \cdot x^2\)
- \(y = C \cdot \ln(x)\)
Answer: B
18. The solution of the differential equation:
\(\frac{dy}{dx} = \frac{x}{y}\)
- \(y^2 = x^2 + C\)
- \(y = \sqrt{x + C}\)
- \(y^2 = x + C\)
- \(y = x + C\)
Answer: A
19. The differential equation:
\(\frac{dy}{dx} = e^x \cdot e^y\)
- \(\frac{dy}{e^y} = e^x \, dx\)
- \(e^{-y} \, dy = e^x \, dx\)
- \(e^y \, dy = e^x \, dx\)
- Both A and B
Answer: D
20. Solve the equation:
\(\frac{dy}{dx} = \frac{1}{y^2}\)
- \(y = \sqrt{x + C}\)
- \(y = \sqrt[3]{x + C}\)
- \(y = \frac{1}{\sqrt{x + C}}\)
- \(y = x + C\)
Answer: C
21. The general solution of the equation:
\(\frac{dy}{dx} = x^2 \cdot y^3\)
- \(y^2 = \frac{1}{x^3 + C}\)
- \(y^2 = \frac{1}{x^3 - C}\)
- \(y^2 = \frac{1}{2x^3 + C}\)
- \(y^2 = \frac{1}{2x^3 - C}\)
Answer: C
22. Which of the following is separable?
- \(\frac{dy}{dx} + y = x\)
- \(\frac{dy}{dx} = x \cdot y\)
- \(\frac{dy}{dx} = x + y\)
- \(y = \sin(x) \cdot \frac{dy}{dx}\)
Answer: B
23. Solve \(\frac{dy}{dx} = \frac{\ln(x)}{y}\).
- \(y^2 = 2\ln(x) + C\)
- \(y^2 = \ln^2(x) + C\)
- \(y = 2\ln(x) + C\)
- \(y = \ln^2(x) + C\)
Answer: A
24. Find the solution of \(\frac{dy}{dx} = x^2 + y^2\).
- \(y = \tan^{-1}(x) + C\)
- \(y = \cot^{-1}(x) + C\)
- \(y^2 + x^2 = C\)
- \(y^2 - x^2 = C\)
Answer: C
25. Solve \(\frac{dy}{dx} = \frac{1 - y^2}{1 + x^2}\).
- \(y = \sin^{-1}(x)\)
- \(y = \cos^{-1}(x)\)
- \(y = \tan^{-1}(x)\)
- \(y = \cot^{-1}(x)\)
Answer: A
26. Solve the differential equation \(\frac{dy}{dx} = y(1 - y)\):
- \(y = \frac{1}{1 + e^{-x}}\)
- \(y = \frac{1}{1 - e^{-x}}\)
- \(y = e^x\)
- \(y = \ln(x)\)
Answer: A
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